Optimal. Leaf size=309 \[ \frac{256 b^4 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{45045 e (d+e x)^{3/2} (b d-a e)^6}+\frac{128 b^3 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{15015 e (d+e x)^{5/2} (b d-a e)^5}+\frac{32 b^2 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{3003 e (d+e x)^{7/2} (b d-a e)^4}+\frac{16 b (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{1287 e (d+e x)^{9/2} (b d-a e)^3}+\frac{2 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{143 e (d+e x)^{11/2} (b d-a e)^2}-\frac{2 (a+b x)^{3/2} (B d-A e)}{13 e (d+e x)^{13/2} (b d-a e)} \]
[Out]
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Rubi [A] time = 0.577748, antiderivative size = 309, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 3, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.125 \[ \frac{256 b^4 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{45045 e (d+e x)^{3/2} (b d-a e)^6}+\frac{128 b^3 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{15015 e (d+e x)^{5/2} (b d-a e)^5}+\frac{32 b^2 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{3003 e (d+e x)^{7/2} (b d-a e)^4}+\frac{16 b (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{1287 e (d+e x)^{9/2} (b d-a e)^3}+\frac{2 (a+b x)^{3/2} (-13 a B e+10 A b e+3 b B d)}{143 e (d+e x)^{11/2} (b d-a e)^2}-\frac{2 (a+b x)^{3/2} (B d-A e)}{13 e (d+e x)^{13/2} (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[(Sqrt[a + b*x]*(A + B*x))/(d + e*x)^(15/2),x]
[Out]
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Rubi in Sympy [A] time = 67.6272, size = 301, normalized size = 0.97 \[ \frac{256 b^{4} \left (a + b x\right )^{\frac{3}{2}} \left (10 A b e - 13 B a e + 3 B b d\right )}{45045 e \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{6}} - \frac{128 b^{3} \left (a + b x\right )^{\frac{3}{2}} \left (10 A b e - 13 B a e + 3 B b d\right )}{15015 e \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )^{5}} + \frac{32 b^{2} \left (a + b x\right )^{\frac{3}{2}} \left (10 A b e - 13 B a e + 3 B b d\right )}{3003 e \left (d + e x\right )^{\frac{7}{2}} \left (a e - b d\right )^{4}} - \frac{16 b \left (a + b x\right )^{\frac{3}{2}} \left (10 A b e - 13 B a e + 3 B b d\right )}{1287 e \left (d + e x\right )^{\frac{9}{2}} \left (a e - b d\right )^{3}} + \frac{2 \left (a + b x\right )^{\frac{3}{2}} \left (10 A b e - 13 B a e + 3 B b d\right )}{143 e \left (d + e x\right )^{\frac{11}{2}} \left (a e - b d\right )^{2}} - \frac{2 \left (a + b x\right )^{\frac{3}{2}} \left (A e - B d\right )}{13 e \left (d + e x\right )^{\frac{13}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)*(b*x+a)**(1/2)/(e*x+d)**(15/2),x)
[Out]
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Mathematica [A] time = 0.528408, size = 256, normalized size = 0.83 \[ \frac{2 \sqrt{a+b x} \left (\frac{128 b^5 (d+e x)^6 (-13 a B e+10 A b e+3 b B d)}{(b d-a e)^6}+\frac{64 b^4 (d+e x)^5 (-13 a B e+10 A b e+3 b B d)}{(b d-a e)^5}+\frac{48 b^3 (d+e x)^4 (-13 a B e+10 A b e+3 b B d)}{(b d-a e)^4}+\frac{40 b^2 (d+e x)^3 (-13 a B e+10 A b e+3 b B d)}{(b d-a e)^3}+\frac{35 b (d+e x)^2 (-13 a B e+10 A b e+3 b B d)}{(b d-a e)^2}-\frac{315 (d+e x) (13 a B e+A b e-14 b B d)}{a e-b d}+3465 (B d-A e)\right )}{45045 e^2 (d+e x)^{13/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(Sqrt[a + b*x]*(A + B*x))/(d + e*x)^(15/2),x]
[Out]
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Maple [B] time = 0.019, size = 722, normalized size = 2.3 \[ -{\frac{-2560\,A{b}^{5}{e}^{5}{x}^{5}+3328\,Ba{b}^{4}{e}^{5}{x}^{5}-768\,B{b}^{5}d{e}^{4}{x}^{5}+3840\,Aa{b}^{4}{e}^{5}{x}^{4}-16640\,A{b}^{5}d{e}^{4}{x}^{4}-4992\,B{a}^{2}{b}^{3}{e}^{5}{x}^{4}+22784\,Ba{b}^{4}d{e}^{4}{x}^{4}-4992\,B{b}^{5}{d}^{2}{e}^{3}{x}^{4}-4800\,A{a}^{2}{b}^{3}{e}^{5}{x}^{3}+24960\,Aa{b}^{4}d{e}^{4}{x}^{3}-45760\,A{b}^{5}{d}^{2}{e}^{3}{x}^{3}+6240\,B{a}^{3}{b}^{2}{e}^{5}{x}^{3}-33888\,B{a}^{2}{b}^{3}d{e}^{4}{x}^{3}+66976\,Ba{b}^{4}{d}^{2}{e}^{3}{x}^{3}-13728\,B{b}^{5}{d}^{3}{e}^{2}{x}^{3}+5600\,A{a}^{3}{b}^{2}{e}^{5}{x}^{2}-31200\,A{a}^{2}{b}^{3}d{e}^{4}{x}^{2}+68640\,Aa{b}^{4}{d}^{2}{e}^{3}{x}^{2}-68640\,A{b}^{5}{d}^{3}{e}^{2}{x}^{2}-7280\,B{a}^{4}b{e}^{5}{x}^{2}+42240\,B{a}^{3}{b}^{2}d{e}^{4}{x}^{2}-98592\,B{a}^{2}{b}^{3}{d}^{2}{e}^{3}{x}^{2}+109824\,Ba{b}^{4}{d}^{3}{e}^{2}{x}^{2}-20592\,B{b}^{5}{d}^{4}e{x}^{2}-6300\,A{a}^{4}b{e}^{5}x+36400\,A{a}^{3}{b}^{2}d{e}^{4}x-85800\,A{a}^{2}{b}^{3}{d}^{2}{e}^{3}x+102960\,Aa{b}^{4}{d}^{3}{e}^{2}x-60060\,A{b}^{5}{d}^{4}ex+8190\,B{a}^{5}{e}^{5}x-49210\,B{a}^{4}bd{e}^{4}x+122460\,B{a}^{3}{b}^{2}{d}^{2}{e}^{3}x-159588\,B{a}^{2}{b}^{3}{d}^{3}{e}^{2}x+108966\,Ba{b}^{4}{d}^{4}ex-18018\,B{b}^{5}{d}^{5}x+6930\,A{a}^{5}{e}^{5}-40950\,A{a}^{4}bd{e}^{4}+100100\,A{a}^{3}{b}^{2}{d}^{2}{e}^{3}-128700\,A{a}^{2}{b}^{3}{d}^{3}{e}^{2}+90090\,Aa{b}^{4}{d}^{4}e-30030\,A{b}^{5}{d}^{5}+1260\,B{a}^{5}d{e}^{4}-7280\,B{a}^{4}b{d}^{2}{e}^{3}+17160\,B{a}^{3}{b}^{2}{d}^{3}{e}^{2}-20592\,B{a}^{2}{b}^{3}{d}^{4}e+12012\,Ba{b}^{4}{d}^{5}}{45045\,{a}^{6}{e}^{6}-270270\,{a}^{5}bd{e}^{5}+675675\,{a}^{4}{b}^{2}{d}^{2}{e}^{4}-900900\,{a}^{3}{b}^{3}{d}^{3}{e}^{3}+675675\,{a}^{2}{b}^{4}{d}^{4}{e}^{2}-270270\,a{b}^{5}{d}^{5}e+45045\,{b}^{6}{d}^{6}} \left ( bx+a \right ) ^{{\frac{3}{2}}} \left ( ex+d \right ) ^{-{\frac{13}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)*(b*x+a)^(1/2)/(e*x+d)^(15/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*sqrt(b*x + a)/(e*x + d)^(15/2),x, algorithm="maxima")
[Out]
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Fricas [A] time = 14.5667, size = 1926, normalized size = 6.23 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*sqrt(b*x + a)/(e*x + d)^(15/2),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)*(b*x+a)**(1/2)/(e*x+d)**(15/2),x)
[Out]
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GIAC/XCAS [A] time = 0.523678, size = 1, normalized size = 0. \[ \mathit{Done} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)*sqrt(b*x + a)/(e*x + d)^(15/2),x, algorithm="giac")
[Out]